图形获胜'无法正确重新加载到D3部队布局中

Graph won't reload properly into D3 force layout

本文关键字：加载 D3 布局 新加载 获胜 图形      更新时间：2023-09-26

我在玩D3，并制作力定向图。我想清除并重新加载图形以响应单击按钮。但是，当我重新加载已经加载的图形时，该图形的格式不正确。这是我正在使用的代码：

<!DOCTYPE html>
<meta charset="utf-8">
<script src="http://d3js.org/d3.v2.js?2.9.1"></script>
<style>
.link {
  fill: none;
  stroke: #666;
  stroke-width: 1.5px;
}
.node circle {
  fill: #ccc;
  stroke: #fff;
  stroke-width: 1.5px;
}
text {
  font: 10px sans-serif;
  pointer-events: none;
}
</style>
<body>
<script>
var all = [
{source: "Tockwotton", target: "List", type: "woodworking"},
{source: "Tockwotton", target: "Prince Lab", type: "woodworking"},
{source: "Prince Lab", target: "Prince Lab", type: "metalworking"},
{source: "Tockwotton", target: "List", type: "cnc"},
{source: "Granoff", target: "Prince Lab", type: "3d-printing"},
{source: "Tockwotton", target: "List", type: "drafting"},
{source: "List", target: "Prince Lab", type: "welding"},
{source: "Prince Lab", target: "Prince Lab", type: "sand-blaster"},
{source: "Tockwotton", target: "List", type: "finishing"},
{source: "Tockwotton", target: "Prince Lab", type: "finishing"},
{source: "Tockwotton", target: "Tockwotton", type: "laser-cutter"}
];
var wood = [
{source: "Tockwotton", target: "List", type: "woodworking"},
{source: "Tockwotton", target: "Prince Lab", type: "woodworking"}
];
var metal = [
{source: "Prince Lab", target: "Prince Lab", type: "metalworking"}
];
var cnc = [
{source: "Tockwotton", target: "List", type: "cnc"}
];
var print = [
{source: "Granoff", target: "Prince Lab", type: "3d-printing"}
];
var draft = [
{source: "Tockwotton", target: "List", type: "drafting"}
];
var weld = [
{source: "List", target: "Prince Lab", type: "welding"}
];
var sand = [
{source: "Prince Lab", target: "Prince Lab", type: "sand-blaster"}
];
var finishing = [
{source: "Tockwotton", target: "List", type: "finishing"},
{source: "Tockwotton", target: "Prince Lab", type: "finishing"}
];
var laser = [
{source: "Tockwotton", target: "Tockwotton", type: "laser-cutter"}
];
function render(linkdata){  
d3.selectAll("svg").remove();
links = linkdata;
nodes = {};
// Compute the distinct nodes from the links.
links.forEach(function(link) {
  link.source = nodes[link.source] || (nodes[link.source] = {name: link.source, type: link.type});
  link.target = nodes[link.target] || (nodes[link.target] = {name: link.target, type: link.type});
});
width = 960,
    height = 500;
force = d3.layout.force()
    .nodes(d3.values(nodes))
    .links(links)
    .size([width, height])
    .linkDistance(60)
    .charge(-300)
    .on("tick", tick)
    .start();
svg = d3.select("body").append("svg")
    .attr("width", width)
    .attr("height", height);
link = svg.selectAll(".link")
    .data(force.links())
    .enter().append("line")
    .attr("class", "link");
node = svg.selectAll(".node")
    .data(force.nodes())
  .enter().append("g")
    .attr("class", "node")
    .on("mouseover", mouseover)
    .on("mouseout", mouseout)
    .call(force.drag);
node.append("circle")
    .attr("r", 8);
node.append("text")
    .attr("x", 12)
    .attr("dy", ".35em")
    .text(function(d) { return d.name; });
function tick() {
  link
      .attr("x1", function(d) { return d.source.x; })
      .attr("y1", function(d) { return d.source.y; })
      .attr("x2", function(d) { return d.target.x; })
      .attr("y2", function(d) { return d.target.y; });
  node
      .attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; });
}
function mouseover() {
  d3.select(this).select("circle").transition()
      .duration(750)
      .attr("r", 16);
}
function mouseout() {
  d3.select(this).select("circle").transition()
      .duration(750)
      .attr("r", 8);
}
}
</script>
<div id="nav">
    <div id="wood">
        <a onclick="render(wood)">Woodworking</a>
    </div>
    <div id="metal">
        <a onclick="render(metal)">Metalworking</a>
    </div>
    <div id="cnc">
        <a onclick="render(cnc)">CNC</a>
    </div>
    <div id="print">
        <a onclick="render(print)">3D Printing</a>
    </div>
    <div id="draft">
        <a onclick="render(draft)">Drafting</a>
    </div>
    <div id="weld">
        <a onclick="render(weld)">Welding</a>
    </div>
    <div id="sand">
        <a onclick="render(sand)">Sand Blast</a>
    </div>
    <div id="finishing">
        <a onclick="render(finishing)">Finishing</a>
    </div>
    <div id="laser">
        <a onclick="render(laser)">Laser Cutting</a>
    </div>
    <div id="all">
        <a onclick="render(all)">All</a>
    </div>
</div>
</body>

尝试一下并注意，第一次单击某个项目时，它运行良好，但如果再次单击，则只会得到一个名为[object Object]的节点。为什么会这样？我该如何解决？

当您使用links = linkdata时，它可能没有达到您期望的效果。与其他一些语言一样，这不会复制数据；相反，它只是使links指向与linkdata指向的相同位置。当你循环遍历links，将它们修改为彼此指向时，你就是在修改数组中的原始对象。当你再次循环浏览它们时，它们已经被修改了，从而导致你正在经历的不良行为。

为了避免这种命运，你需要在修改数组之前对其进行深度复制。有很多方法可以做到这一点，但你需要确保无论使用什么解决方案，都会将数组克隆为数组，而不会将其变成普通的Object。

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