SyntaxError:JSON.parse:使用d3.js的JSON数据的第2行第14列的字符串文字中存在错误的控制字

SyntaxError: JSON.parse: bad control character in string literal at line 2 column 14 of the JSON data with d3.js

本文关键字：JSON 字符串 文字 错误 控制 14列 存在 使用 parse d3 js      更新时间：2023-09-26

我正试图用http://bl.ocks.org/mbostock/2966094.我用json数据替换了tree.json，并对代码进行了一些修改，但它似乎不起作用。

structure.html

    <!DOCTYPE html>
<meta charset="utf-8">
<style>
text {
  font-family: "Helvetica Neue", Helvetica, sans-serif;
}
.name {
  font-weight: bold;
}
.about {
  fill: #777;
  font-size: smaller;
}
.link {
  fill: none;
  stroke: #000;
  shape-rendering: crispEdges;
}
</style>
<body>
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.5.5/d3.min.js"></script>
<script>
var margin = {top: 0, right: 320, bottom: 0, left: 0},
    width = 960 - margin.left - margin.right,
    height = 500 - margin.top - margin.bottom;
var tree = d3.layout.tree()
    .separation(function(a, b) { return a.parent === b.parent ? 1 : .5; })
    .children(function(d) { return d.parents; })
    .size([height, width]);
var svg = d3.select("body").append("svg")
    .attr("width", width + margin.left + margin.right)
    .attr("height", height + margin.top + margin.bottom)
  .append("g")
    .attr("transform", "translate(" + margin.left + "," + margin.top + ")");
d3.json("tree.json", function(error, json) {
  if (error) throw error;
  var nodes = tree.nodes(json);
  var link = svg.selectAll(".link")
      .data(tree.links(nodes))
    .enter().append("path")
      .attr("class", "link")
      .attr("d", elbow);
  var node = svg.selectAll(".node")
      .data(nodes)
    .enter().append("g")
      .attr("class", "node")
      .attr("transform", function(d) { return "translate(" + d.y + "," + d.x + ")"; })
  node.append("text")
      .attr("class", "name")
      .attr("x", 8)
      .attr("y", -6)
      .text(function(d) { return d.vision; });
  node.append("text")
      .attr("class", "name")
      .attr("x", 8)
      .attr("y", -6)
      .text(function(d) { return d.actor; });
/*  node.append("text")
      .attr("x", 8)
      .attr("y", 8)
      .attr("dy", ".71em")
      .attr("class", "about lifespan")
      .text(function(d) { return d.born + "–" + d.died; });*/
/*  node.append("text")
      .attr("x", 8)
      .attr("y", 8)
      .attr("dy", "1.86em")
      .attr("class", "about location")
      .text(function(d) { return d.location; });*/
});
function elbow(d, i) {
  return "M" + d.source.y + "," + d.source.x
       + "H" + d.target.y + "V" + d.target.x
       + (d.target.children ? "" : "h" + margin.right);
}
</script>

tree.json

{
  "value": "{'"vision'":['"For Commuters who Spend hell lot of time in traffic  is a Traditional Commuting solution that Tracking enabled mobile App unlike Sharing the rides our product Car pooling '",'"For Commuters who Spend hell lot of time in traffic  is a Traditional Commuting solution that Tracking enabled mobile App unlike Sharing the rides our product Car pooling '"],'"actors'":['"Commuters'",'"Government'"]}"
}

观察您的JSON:

{
    "value": "{"vision":["For Commuters ... "]}"
}

您的"value"的value在字符串中。这是一个JSON对象，不应声明为字符串。以下是正确的格式(请参阅我删除的引号(：

{
    "value": {"vision":["For Commuters ... "]}
}

从我读到的评论中，当您在jsonlint中粘贴JSON时，您得到了一个有效的JSON。那是因为jsonlint认为你写了这样的东西：

{
    "value": "another_value"
}

由于JSON对象是用引号括起来的，jsonlint将其作为一个文本字符串。

附言：在你的标题中，你自己也提到错误在第2行第14列。计算第2行和第14列中的内容——这是您需要删除的"字符。

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